-12x^2=34x+-28

Solution for -12x^2=34x+-28 equation:

-12x^2=34x+-28

We move all terms to the left:

-12x^2-(34x+-28)=0

We add all the numbers together, and all the variables

-12x^2-(34x-28)=0

We get rid of parentheses

-12x^2-34x+28=0

a = -12; b = -34; c = +28;
Δ = b2-4ac
Δ = -342-4·(-12)·28
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-50}{2*-12}=\frac{-16}{-24}
=2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+50}{2*-12}=\frac{84}{-24}
=-3+1/2
$